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Hastati

Posted: Mon Oct 26, 2020 3:52 am
by ochoin
Partly because I need to consolidate my Polybian Roman army (mostly HaT & Zvesda figures) and partly because there was a Newline sale on, I bought another Roman legion : which make a fourth & final one.

The figures painted so far are Hastati. I've been thinking of giving them a Syracusan Greek ally as I have some units of Greek spear & slingers painted from years ago. I'll need to re-visit Newline to bring the slingers up to strength & buy some thureophori & a general.

The Hastati:
Image

Image

Image

8 Triari, 8 Velites, 16 Principes (including command) to go.

donald

Re: Hastati

Posted: Mon Oct 26, 2020 10:07 am
by grizzlymc
Excellent. Now you can play with yourself and learn how to defeat them.

Re: Hastati

Posted: Mon Oct 26, 2020 10:29 am
by Essex Boy
Very impressive, Donald.

The bases are a little cornery for my taste, but the whole is a splendid sight.

Iain

Re: Hastati

Posted: Mon Oct 26, 2020 11:08 am
by grizzlymc
Ocho, you know the kewl kidz are using dodecagonal baser.

Re: Hastati

Posted: Mon Oct 26, 2020 11:35 am
by ochoin
I appreciate the feedback. The FoG rules are quite hidebound on mathematical precision.

Indeed, in the Index pages, on basing, the rule book states:

Let f(x)=log(1+|x|) for x∈R and g(x)=log(1+x) for x>−1
Then:

limx→0+f(x)−f(0)x−0=limx→0+g(x)−g(0)x−0=g′(0)=1
and

limx→0−f(x)−f(0)x−0=limx→0−g(−x)−g(0)x−0=−limx→0−g(−x)−g(0)−x−0=−g′(0)=−1


Can't argue with that.

donald

Re: Hastati

Posted: Mon Oct 26, 2020 11:40 am
by grizzlymc
Tell me that you are joking, please!

Re: Hastati

Posted: Mon Oct 26, 2020 3:21 pm
by BaronVonWreckedoften
Don't forget the optional ursine intercession rule - if all else fails, shoot the bear.

Re: Hastati

Posted: Mon Oct 26, 2020 8:35 pm
by Essex Boy
ochoin wrote: Mon Oct 26, 2020 11:35 am I appreciate the feedback. The FoG rules are quite hidebound on mathematical precision.

Indeed, in the Index pages, on basing, the rule book states:

Let f(x)=log(1+|x|) for x∈R and g(x)=log(1+x) for x>−1
Then:

limx→0+f(x)−f(0)x−0=limx→0+g(x)−g(0)x−0=g′(0)=1
and

limx→0−f(x)−f(0)x−0=limx→0−g(−x)−g(0)x−0=−limx→0−g(−x)−g(0)−x−0=−g′(0)=−1


Can't argue with that.

donald
I bet I could argue with it. I have a gift in that respect.

Re: Hastati

Posted: Mon Oct 26, 2020 11:30 pm
by ochoin
You do calculus?

I actually got that off the boy-genius who uses it in his job.
Something to do with corners, he tells me.

donald

Re: Hastati

Posted: Mon Oct 26, 2020 11:49 pm
by Essex Boy
ochoin wrote: Mon Oct 26, 2020 11:30 pm You do calculus?

I actually got that off the boy-genius who uses it in his job.
Something to do with corners, he tells me.

donald
Nope. I do arguments.

The boy-genius is a credit to his parents.